2[3(x-1)]+x=1

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Solution for 2[3(x-1)]+x=1 equation:


Simplifying
2[3(x + -1)] + x = 1

Reorder the terms:
2[3(-1 + x)] + x = 1
2[(-1 * 3 + x * 3)] + x = 1
2[(-3 + 3x)] + x = 1
[-3 * 2 + 3x * 2] + x = 1
[-6 + 6x] + x = 1

Combine like terms: 6x + x = 7x
-6 + 7x = 1

Solving
-6 + 7x = 1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 7x = 1 + 6

Combine like terms: -6 + 6 = 0
0 + 7x = 1 + 6
7x = 1 + 6

Combine like terms: 1 + 6 = 7
7x = 7

Divide each side by '7'.
x = 1

Simplifying
x = 1

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